Figure 1.
The acceleration equation is known as Coriolis' theorem as it was
presented by Gaspard Gustave de Coriolis in 1835. Hereafter, we
ignore the last term to consider only systems that rotate at a
constant angular velocity. In the inertial system, a particle of
mass m subject to a force Substitution of Eq. (2)
into Eq. (3)
leads to the equation of motion in the rotating frame:
The rotating observer thus postulates two new forces to explain
the motion of the particle. These new forces go by a
variety of names: "inertial" forces, because they represent the
inertia of the body; "noninertial" forces, because they arise from
being in a noninertial frame; or "fictitious" or "pseudo" forces,
because they are artifacts of being in a noninertial reference
frame. The first new term on the right-hand side of Eq.
(4)
is called the centrifugal force,
and points away from the axis of rotation. The second new term on
the right-hand side of Eq. (4)
is called the Coriolis force and is often written as
where
To generate the complete great circle,
and have been written with the intent of solving them for the
parameters
where Figure 6(b)
shows the inertial great circle along which the puck moves, and
the naïve earthbound great circle at the time of launch and at a
later time after the earth has rotated. In general, the inertial and
earthbound great circles have different initial headings, and so
reach different maximum latitudes. The two headings [Eqs. (13)
and (14)]
are coincident only when
Expressing these in terms of parameters measured by the earthbound
observer results in
In order to illustrate the physical significance of each term in
these expansions, we consider a succession of specialized cases with
simple initial conditions, as was done in Fig. 3,
and then finish with the general case. We will see that the
first-order terms represent the expected motion of the puck on a
stationary flat earth plus the angular displacement of the rotating
earth, while the second-order terms represent the effects of inertial
forces and the curvature of the earth.
The inertial observer credits the longitudinal displacement to the
initial velocity of the puck, with contributions from the rotating
earth's velocity ( at latitude where the displacement is assumed to be small enough that the
latitude can be taken as a constant equal to the starting latitude.
This southward displacement calculated by the earthbound observer is
equivalent to the displacement calculated by the inertial observer
( at latitude where again in contrast to the earth heading of
The expected northward range of the puck [term in Eq. (29)
which results in an eastward displacement after a time t
(assumed small) of
Both displacements calculated by the rotating observer are shown
as arrows in Fig. 8,
and again agree with the inertial description of the motion for small
times. Note that there is no curvilinear correction in this case
since the expected path along the meridian is a great circle
(coincident with the line of sight to the north).
Fig. 1. A rocket launched along the prime meridian from the North
Pole continues south (the medium thickness solid line) along a
meridian fixed in the inertial frame. The intended earthbound route
(the dashed line) moves east with the earth, and the rotating
observer sees the rocket follow a curved path (the thickest solid
line) that deflects to the right of the intended path. First
citation in article
Fig. 2. (a) Motion of a puck released from rest with respect to a
rotating turntable from position A. After a time t, the
initial position of the puck has rotated from A to
A*. The inertial observer sees the puck follow the
straight line from A to C, while the rotating observer
sees the puck follow the curved path from A* to
C. (b) Motion of a puck launched with a speed Fig. 3. (a) Motion of a puck launched to the east on a
stationary earth. The puck travels along a great circle path
from A to B. On a flat earth, the puck would
always travel east and end up at F. (b) Inertial view of
the motion of a puck released from rest with respect to the rotating
earth. The puck travels along the inertial great circle path from
A to C in a time t. After the time t, the
earthbound observer has moved along the original line of latitude
from A to A*, and has seen the puck move
along the path from A* to C. (c) Motion of a
puck that is launched eastward with respect to the rotating
earth. The puck is launched from position A at time t =
0 toward a target located at position B. After a time
t, the launch site and the target have rotated to
positions A* and B*, respectively. The
target on a flat earth would be at F (rotated to
F* after time t). The inertial observer sees
the puck travel along the great circle from A to C,
while the earthbound observer sees the puck move along the path from
A* to C, missing the intended target at
B*. The puck would end up at C0
if the initial velocity with respect to the earth were zero. (d)
Motion of a puck that is launched to the north with respect to
the rotating earth. The description of the motion is the same
as in (c) above. The flat earth target F is coincident
with the target B. First
citation in article
Fig. 4. (a) Motion of a puck launched to the east with an inertial
speed equal to the speed of the earth at the equator. The inertial
observer sees the puck follow the great circle shown (the
thickest line), while the earthbound observer sees the puck follow
the figure-eight path. (b) Motion of a puck launched to the
west with a speed slightly less than the local speed of the
earth. The inertial observer sees the puck move east along the great
circle (the thickest line), while the earthbound observer sees the
puck follow the westward path spiraling away from the pole. First
citation in article
Fig. 5. Coordinate systems for the description of a great circle.
The general great circle (the thickest line) lies in the
x Fig. 6. (a) Initial heading of the puck as measured in inertial
and rotating (earth) frames. The puck has velocity components Fig. 7. Motion of a puck that is launched eastward with respect to
the rotating earth for short times. The description of the motion
from launch site to target is the same as in Fig. 3(c).
The arrows indicate the curvilinear displacement of the target from
the original line of latitude and the calculated centrifugal and
Coriolis displacements of the puck from the target. First
citation in article
Fig. 8. Motion of a puck that is launched to the north with
respect to the rotating earth. The description of the motion from
launch site to target is the same as in Fig. 3(d).
Both axes are broken in order to show launch and target locations at
both times and the small corrections. As shown in the spherical
plot of Fig. 3(d),
the paths from A to C and A* to
C are curved, but in this plot all the curvature is hidden in
the broken region of the plot (thin dotted lines). The arrows
indicate the calculated centrifugal and Coriolis displacements of the
puck from the target. First
citation in article
Fig. 9. Motion of a puck that is launched to the northeast with
respect to the rotating earth. Short times are shown in the
main plot and longer times are shown in the spherical plot. The
heading for this case is
aElectronic mail: mcintyre@ucs.orst.edu Up: Issue
Table of Contents
.
Considering the motion of a particle at position
, the relations between the velocities and accelerations
as measured in the two coordinate systems are12
obeys
Newton's equation of motion:
r is the velocity
relative to the rotating system. The Coriolis force causes deflection
perpendicular to the motion in the rotating frame. III. QUALITATIVE DISCUSSION
R
arising from the rotation of the turntable. The inertial observer
sees the puck follow the straight path from A to C,
while the rotating observer rotates from A to
A* and sees the puck follow the path from
A* to C, taking it to larger radii. The
rotating observer aware of the rotation (hereafter referred to simply
as the "rotating observer") invokes the centrifugal force to explain
why the puck drifts to larger radii, while the inertial observer
claims it is a simple consequence of the inertial motion of the puck
combined with the acceleration of the rotating observer. In Fig. 2(b)
the puck is launched from the origin toward a target B on
the turntable. The naïve rotating observer would expect the puck
to follow a straight path, shown in Fig. 2(b)
as A to B*, where B* is
the rotated inertial position of the target after some time t.
The inertial observer sees the puck follow the straight path from
A to C, while the rotating observer sees the puck
follow the curved path from A to C, which clearly
misses the target B*. The rotating observer invokes
the Coriolis force to explain the deflection, while the inertial
observer claims it is a simple consequence of the inertial motion of
the puck combined with the acceleration of the target. These two
simple examples illustrate that inertial straight-line motion is
transformed into more complicated, and in general curved, motion when
viewed from the rotating frame.
Figure 2.
Figure 3.
start. A naïve earthbound observer would
expect the puck to remain at its initial location on the earth. An
inertial observer notes that the puck has an eastward speed equal
to the speed of the surface of the earth at the initial
latitude,
earth =
R cos
start.
The puck travels along the inertial great circle shown in Fig. 3(b)
and after some time arrives at position C. During that time,
the earthbound observer travels along the original line of latitude
from the initial position of the puck A to a new position
A* in the inertial frame. Thus the earthbound
observer sees the puck follow the path from A* to
C (not a great circle). The inertial observer explains this
relative motion as the difference between the great circle path of
the puck and the fixed latitude of the earthbound observer. The
earthbound observer explains the southward motion by invoking the
centrifugal force [Eq. (5)],
which points away from the axis of rotation and has upward and
southward components, as shown in Fig. 3(b).
The upward component simply reduces the normal force and hence
the apparent weight of the puck. The southward component is
responsible for the southward displacement of C from
A*. Note that the westward displacement evident in
Fig. 3(b)
is a higher-order effect caused by the Coriolis force due to the
acquired southward motion (see the discussion of north–south motion
below), and will not be evident when we focus on small
times in the quantitative analysis later.
E so that the inertial
speed of the puck (i.e., as measured by the inertial observer)
is
E +
earth. The puck follows the same inertial
great circle path as in Fig. 3(b),
with an increased speed along the path. Figure 3(c)
shows the path of the puck and the initial and final inertial
positions of the earthbound observer (A and
A*), the target (B and B*),
the target expected on a flat earth (F and
F*), and the final inertial position of the puck
(C). The puck moves along the inertial great circle from
A to C, which in this case is coincident with the
earthbound great circle that the puck would follow on a
stationary earth since the initial velocity is to the east in
both frames. After some time, the expected earthbound path (A
to B) has rotated (it appears as A* to
B*) and the inertial path from A to C
transformed into the earth frame appears as the path from
A* to C (which is not a great circle),
taking the puck south of the flat-earth target F*
and south of the spherical-earth target B*. Once
again, the inertial observer explains the southward relative motion
(F* to C) as the difference between the
great circle path of the puck and the original circle of latitude.
The earthbound observer attributes the southward displacement to
three effects. The curvilinear correction [see Fig. 3(a)]
accounts for the difference between the flat-earth target
F* and the spherical-earth target
B*. The centrifugal effect alone (i.e., when
E =
0) would cause the puck to end up at C0, which
corresponds to position C in Fig. 3(b).
The additional displacement in latitude to C is attributed to
the Coriolis force that the earthbound observer invokes due to the
puck's motion in the rotating frame. The Coriolis force [Eq. (6)]
for eastward motion points away from the axis of rotation and
has upward and southward components, as shown in Fig. 3(c).
The upward component again reduces the normal force and hence
the apparent weight of the puck. The southward component is
responsible for the displacement of the puck, which is to the
right of the velocity in the rotating frame (in the Northern
Hemisphere).
R).
The puck follows an inertial great circle and takes one day to
return to its inertial starting point, at which time the earthbound
observer also returns, as shown in Fig. 4(a). The earthbound observer sees the puck follow a
figure-eight-shaped path, always turning to the right in the Northern
Hemisphere and to the left in the Southern Hemisphere, which is
attributed to the combined effect of the centrifugal and Coriolis
forces. This boomerang-type path can be obtained with any initial
heading, as long as the inertial speed of the puck is
R. Next consider a puck launched to the west
with a speed slightly less than the local earth speed. The
inertial observer sees the puck travel east very slowly, such that
the earth rotates many times before the puck travels once around the
inertial great circle. The earthbound observer sees a path headed
west and slightly south of the original line of latitude, resulting
in a spiral around the pole as shown in Fig. 4(b).
In this case, the earthbound observer sees the puck continually
turning to the right (with respect to the naïve earthbound great
circle), since the Coriolis force dominates the centrifugal force.
Figure 4.
of the earth, but is not matched should the puck
rotate at a different frequency. This concept provides a common
explanation of the Coriolis force from the inertial viewpoint.3,9
A hockey puck launched to the east has an inertial velocity
faster than that of the local surface of the earth. The
net centripetal force that kept it at rest before is now not
sufficient to keep the puck traveling in a circle at this speed, so
the puck moves to a larger radius where there is a smaller
centripetal acceleration (
2/r). The
eastward-launched puck thus moves southward, explaining the rightward
Coriolis deflection (in the Northern Hemisphere). A puck launched to
the west is traveling too slowly and moves to a smaller
radius where there is a larger centripetal acceleration. The
westward-launched puck moves northward, again to the right (in the
Northern Hemisphere). In the rotating frame, the deflection of the
puck from its intended target is due only to the Coriolis
force. This is why discussions of the effects of rotation upon
the weather, ocean currents, and rivers on our oblate earth invoke
only the Coriolis force. IV. QUANTITATIVE ANALYSIS
A. Great circles
,
measured as positive (negative) for the Northern (Southern)
Hemisphere, and the longitude
, measured counterclockwise from the prime
meridian, which lies in the xz plane. The equator is the great
circle in the xy plane, and is described simply by
= 0.
Any other general great circle is considered as the equator in a
primed x
y
z
coordinate system, which is obtained by rotating the unprimed system
first about the z axis by an angle
0 and
then about the new y
axis by an angle
max. All possible great circles can be
accessed using rotation angles 0
0
2
and 0
max
/2. In the primed coordinate system, the equation
of the great circle is simply 
= 0, where 
and 
are the latitude and longitude, respectively,
as measured in that system. In the unprimed coordinate system, this
general great circle reaches a maximum latitude
max at
a longitude
0. By transforming the equation 
= 0 back to the unprimed frame or
by requiring that the normal vector to the great circle plane
be perpendicular to any general vector in that plane, it is
straightforward to show that the equation of the general great circle
in the unprimed coordinate system can be written as
Figure 5.
along the great circle, beginning at 
=

at time
t = 0, can be described simply by 
(t) = 
+
t, 
(t) = 0, where the angular speed
= ±
/R and the plus (minus) sign denotes
motion that is counterclockwise (clockwise) when viewed looking down
from the positive z
axis. In the unprimed system, the great circle path can be written
parametrically as
must be added to
the longitude
(t) obtained by solving Eq. (9)
for part of the path, since the inverse trigonometric functions have
limited principal values. This is not a problem when solving Eq. (7)
or (8)
for
.
max,
0, and 
, whereas most problems
are posed in terms of the initial position
start,
start and the initial heading, which we
denote by the angle
with respect to local east. Figure 5
shows an earthbound reference frame with the origin at the initial
position of the puck and X coincident with local east,
Y with local north, and Z with local up (along the
radius vector). As shown in Fig. 5,
the initial heading
is measured as positive in the counterclockwise sense
toward the north. The equations relating these two sets of great
circle parameters are
max,
0, and 
. The absolute
value in Eq. (10)
ensures that
max is within the range 0–
/2 for all starting
conditions. Since the principal values of the inverse trigonometric
functions are limited, one must add or subtract
when solving Eqs. (11)
and (12)
to find
0–
start and 
for the case
start<0. Equation (12)
can be written more simply, but the form shown ensures that

takes on the proper
values (for
start>0) when the equation is inverted
to find 
in terms of
start and
. B. Terrestrial ice hockey
with respect to the inertial frame. The
great circle equations derived above are used to describe great
circles in both the inertial and rotating frames. We work primarily
with the latitude–longitude coordinate description of the motion,
which makes the transformation from one frame to the other
simple—only the longitudinal difference
t due to
the rotation is required.
E and
N are the east and north
components of the initial velocity of the puck relative to the
earth. The rotation of the earth causes the inertial observer to
measure the puck's initial heading as
N = 0, i.e., for motion that is
initially east or west, or when
start =
±
/2, i.e.,
for motion from the poles. The inertial observer notes that the puck
has an angular velocity along the inertial great circle of
Figure 6.
t. This yields terms of the same
order as the lowest-order calculations of noninertial effects in the
rotating frame. It is these lowest-order terms that we compare. These
expanded great circle equations giving the inertial position of the
puck are
E in the eastward direction by
the earthbound observer. The motion of the puck was depicted in
the spherical plot of Fig. 3(c).
An expanded plot of the path of the puck for short times is
shown in Fig. 7 with an equirectangular projection (simple latitude
versus longitude) and notation equivalent to Fig. 3(c).
Since there is only an eastward initial velocity in this case, the
expanded equations for the inertial position of the puck are
t, corresponding to A to
A*) and the launch speed with respect to the earth
(term![[proportional]](GreatCircles_files/prop.gif)
Et, corresponding to
A* to F*). The inertial observer
credits the latitudinal displacement to the inertial motion along the
great circle, which takes the puck south of the original line of
latitude. Since the inertial motion is composed of the motion of the
puck with respect to the earth and the motion of the earth,
the squared term of Eq. (21)
gives rise to three terms, as shown in Eq. (22).
Thus, what the inertial observer credits to a single effect, the
rotating observer credits to three effects, which, in order of
appearance in Eq. (22),
correspond to the three effects demonstrated in Figs. 3(a),
(b), and (c), respectively. The first term [
(
E/R)2] corresponds to
the curvilinear effect described above whereby the target seen to
the east is at a lower latitude. This is depicted in Fig. 7
by the arrow between the flat earth target F and the spherical
earth target B. Note that this curvilinear correction becomes
zero on a flat earth (R
), as one would expect.
Figure 7.
![[proportional]](GreatCircles_files/prop.gif)
2) corresponds to the centrifugal force,
which was depicted in Fig. 3(b).
The earthbound observer notes that the surface component of the
centrifugal force points to the south and results in an
acceleration of
. After a time t, this acceleration results in
a displacement
Y = R.gif)
) using the second correction term in
Eq. (22)
and is represented in Fig. 7
by the arrow from the final position of the earthbound observer
A* to the final position the puck would have if it
were released from rest (
E = 0), which is labeled
C0. ![[proportional]](GreatCircles_files/prop.gif)

E) corresponds to the
Coriolis force, which was depicted in Fig. 3(c).
The surface component of the Coriolis force results in an
acceleration of
. After a time t, this acceleration results in
a displacement
is assumed constant for small t. This
southward displacement again matches the inertial term and is shown
as the arrow ending at C in Fig. 7.
The arrows depicting the other two effects are duplicated at the
final longitude to show that all three latitude correction terms
contribute to explain the displacement of the puck (C) from
the flat earth target (F*). Thus the lowest-order
displacements calculated by a rotating observer using inertial forces
agree with the calculation of the inertial observer for short times,
and so the two observers agree on the motion of the puck but not on
the physics behind the motion. Note that the higher-order westward
displacement discussed earlier in regard to Fig. 3(b)
is not evident for the short times shown in Fig. 7.
N with respect to the
earth. In this case, the motion of the earth's surface leads the
inertial observer to measure a heading given by
earth =
90°. The great circle motion of the puck on the earth was
shown in Fig. 3(d).
An expanded view of the motion for small times is shown in Fig. 8, with notation equivalent to Fig. 3(d).
Since there is only a northward initial velocity (in the earth frame)
in this case, the expanded equations for the inertial position of the
puck are
![[proportional]](GreatCircles_files/prop.gif)
N] is reduced by the same southward
centrifugal deflection calculated above [Eq. (24)].
The longitude exhibits the rotation of the earth (
t) and a
correction term that corresponds to the Coriolis force. For a
northward velocity, the Coriolis force is solely to the east [to the
right again, as shown in Fig. 3(d)]
and causes an acceleration of
Figure 8.
![[proportional]](GreatCircles_files/prop.gif)
E
N),
which is another curvilinear correction and is shown as the arrow
ending at B* in Fig. 9.
The deflection of the puck from the target (for small times) is
a combination of the previously discussed terms and includes the
southward centrifugal deflection [Eq. (24)]
and both southward [Eq. (26)]
and eastward [Eq. (31)]
Coriolis deflections (which are combined into one arrow in Fig. 9).
Figure 9.
V. SUMMARY
ACKNOWLEDGMENTS
REFERENCES
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Corinne A.
Manogue et al., Am. J.
Phys. 69, 978 (2001) FIGURES
Full figure (8 kB)
Full figure (7 kB)
from the
center of the turntable toward a target B on the turntable.
After a time t, the target has rotated from B to
B*. The inertial observer sees the puck follow the
straight line from A to C, while the rotating observer
sees the puck follow the curved path from A to C, which
deviates from the straight path from A to B*
as expected if rotation is ignored. First
citation in article
Full figure (16 kB)
Full figure (9 kB)
Full figure (8 kB)
y
plane. Also shown are the equator in the xy plane and the line
of latitude corresponding to the maximum latitude
max
reached by the great circle. The maximum latitude is reached at a
longitude of
0. The earthbound observer uses the
XYZ coordinate system with origin at the initial position of
the puck. The initial inertial position of the puck is latitude
start and longitude
start
with initial heading
, measured counterclockwise from local east. First
citation in article
Full figure (10 kB)
E and
N to the east and north,
respectively, as measured in the earth frame. The speed of the earth
at the initial puck position is
earth =
R cos
start. (b) Great circle path of the
puck as seen by an inertial observer (the thickest line). The
puck is launched from position A, which rotates to position
A* after a time t. The great circle path
that the puck would follow on a nonrotating earth is shown
both at the time of launch and after the earth has rotated.
First
citation in article
Full figure (9 kB)
Full figure (12 kB)
Full figure (14 kB)
earth = 60°, with a speed (in
the earth frame) of
earth, which gives an inertial heading of
inertial = 30°. The description of the motion
from launch site to target is the same as in Fig. 3(c).
Only the final positions of the puck (C) and the intended
target (B* on a spherical earth and F*
on a flat earth) are shown in the main plot; the labels
A and A* denote the origins of the
respective paths. The two curvilinear arrows indicate the difference
between the constant heading path from A* to
F* and the great circle path (or line of sight)
from A* to B*. The other arrows
indicate the calculated centrifugal and Coriolis displacements of the
puck from the target. First
citation in article
FOOTNOTES
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