Momentum

 

Momentum is proportional to mass of object.

Momentum is proportional to velocity of object.

Momentum is EQUAL to the product of an object’s mass and velocity.

            p = m v

 

The units for momentum will be  kg m/s (SI). There is no special name for momentum units.

 

Momentum is a vector quantity. Direction matters.

 

Momentum (in physics) is not to be confused with a winning football team’s momentum (NOT physics)!


Impulse

 

Momentum, by itself has only limited usefulness (and  excitement!) It gets more interesting when momentum is changing.

 

To hit a baseball a long ways (by changing its momentum in a big way), you want to increase both the force of the bat on the ball (how hard you swing), and the time of contact between the bat and ball (follow-through.)

 

Newton defined impulse to be the (average) force on an object multiplied by the time during which that force is applied.

J = F Δt

Note the units for impulse will be N s.

Note relationship between this and Newton’s Second Law:

            F = m a = m Δv / Δt          multiply both sides by Δt

 

            F Δt = m Δv = Δp

 

This gives us the:


Impulse-Momentum Theorem

 

The impulse applied to an object EQUALS the change in momentum of that object.

F Δt = m Δv = Δp

 

(Newton actually framed his second law in terms of impulse and momentum rather than force and acceleration.)

 

This concept can make some problems that are difficult to do otherwise easier/possible.

 

Scene from Apollo 13…

 

“Cushioning” a catch (of a water balloon, egg, or barehanded softball or baseball).

- To catch a thrown egg, you need to change its   

   momentum to zero. (A fixed value for a given

   initial velocity.)

- “Cushioning” your catch extends the interaction time.

- Increasing the time of impulse decreases the force!

 

Note units:       N s = kg m/s    Same!


Momentum (continued)

 

Momentum is very useful in interactions between objects.

- If object A exerts a force on object B and changes object B’s

   momentum, then the equal but opposite force of object B on

   object A will change object A’s momentum by exactly the same

   amount but in the opposite direction.

      - The forces must be the same (Newton’s 3rd Law), the time of

   interaction must be the same (B is touching A as long as A is

   touching B), therefore the impulse on B must be exactly the

   same as the impulse on A, therefore the change in momentum of

   B must equal exactly the change in momentum of A.

      - This is quite similar to, but often more useful than,

   Newton’s 3rd Law.

 

Law of Conservation of Momentum

      - If there are no outside forces acting on a system of objects, then

  the total momentum of the system stays constant.

- This is a VERY useful and important concept.

       - collisions (from car crash analysis to interactions of

  colliding galaxies to interactions of atoms and molecules…)

       - recoil (guns, cannons…)

       - rocket and/or jet propulsion

       - ballistics (muzzle velocity of a gun), bomb trajectory

       - Problems where forces are hard or impossible to measure

                can be solved with this concept.


Collisions

Collision

Type

Characteristics

Examples

Kinetic Energy Conserved?

Momentum Conserved?

 

Perfectly or

Totally Elastic

Objects bounce off each other with NO damage or permanent deformation

 

Atoms and molecules

 

Yes

 

Yes

 

(Approximately)

Elastic

 

Objects bounce off each other with negligible damage or permanent deformation

 

Pool balls, steel ball off marble, rubber bouncy balls, golf ball off club

 

 

Very Nearly

(Yes, for our problems)

 

Yes

 

Inelastic

 

Objects bounce off each other with permanent damage or deformation

Most car crashes, people bumping, any collision that isn’t perfectly inelastic but KE losses are large*

 

No

 

Yes

 

Perfectly or Totally Inelastic

 

Any collision where objects stick together

Bullet imbedded in an object, a football tackle, trains coupling, jumping into a boat, catching a ball…

 

No

 

Yes

* There is a continuum between collisions that are approximately elastic and inelastic, depending on how much KE is conserved. A golf club hitting a golf ball can have more than 80% of KE conserved (transferred) whereas a “dead” tennis ball off a racket may have less than 40% KE conserved.

 

Note that in all these cases, momentum is conserved! The conservation of momentum makes it possible to solve a large number of different types of problems.


Conservation of Momentum (continued)

 

Possibly the easiest way to set up these problems is to

1) Identify clearly the interaction in question.

2) Set up the (vector) sum of all momenta before the interaction.

3) Set up the (vector) sum of all momenta after the interaction.

4) Equate the two sums!

 

            Σ pbefore = Σ pafter

 

All conservation of momentum problems can be set up this way.

 

Elastic collisions may require simultaneously solving conservation of KE equation with conservation of momentum equation.

 

2-D problems require that you isolate x and y components of the momentums, but the concept is the same!

Σ px-before = Σ px-after

 

Σ py-before = Σ py-after